Question

A journal bearing with diameter of 76.2 mm is subjected to a load of 4900 N while rotating at 200 rpm. If its coefficient of friction is 0.02 and the I/D = 2.5, find its projected area in mm

Answer 1

490 mm².

Step-by-step explanation:

To find the projected area of the journal bearing, we can use the formula:

Projected Area = Load / (Coefficient of friction * RPM * I/D)

Given:

Diameter of the bearing = 76.2 mm

Load = 4900 N

Coefficient of friction = 0.02

RPM = 200

I/D = 2.5

Let's substitute these values into the formula:

Projected Area = 4900 / (0.02 * 200 * 2.5)

Simplifying the expression:

Projected Area = 4900 / (0.02 * 500)

Projected Area = 4900 / 10

Projected Area = 490 mm²

Therefore, the projected area of the journal bearing is 490 mm².