Question

Solve the right triangle. Side lengths to nearest tenth and angles to nearest WHOLE number

Please help I don’t have a lot of time

Answer 1

see explanation

Explanation:

the sum of the 3 angles in a triangle is 180° , that is

∠ A + ∠ B + ∠ C = 180° ( substitute ∠ A = 47° , ∠ C = 90° )

47° + ∠ B + 90° = 180°

∠ B + 137° = 180° ( subtract 137° from both sides )

∠ B = 43°

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using the sine ratio in the right triangle

sin47° =
`(opposite)/(hypotenuse)` =
`(BC)/(AB)` =
`(BC)/(3)` ( multiply both sides by 3 )

3 × sin47° = BC , then

BC ≈ 2.2 ( to the nearest tenth )

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using the cosine ratio in the right triangle

cos47° =
`(adjacent)/(hypotenuse)` =
`(AC)/(AB)` =
`(AC)/(3)` ( multiply both sides by 3 )

3 × cos47° = AC , then

AC ≈ 2.0 ( to the nearest tenth )