Question

Solve the right triangle. Side lengths to nearest tenth and angles to nearest WHOLE number

Please help I don’t have a lot of time

Answer 1

m∠B = 180-90-47=43°

BC :

we know the opposite angle to BC = CÂB =47°.

we know the hypotenuse = 3

sin(47)=CB/AB

BC= 3*sin(47)=2.194..=2.2

calculate AC

pythagoras

AC²= AB²-BC²

AC² = 3²-2.2²

AC =V4.16=2.03..=2

Explanation: