Answer: 0
Explanation:
The standard form of a circle with center (h,k) and radius r is given by the equation (x-h)^2 + (y-k)^2 = r^2 1.
In this case, the given equation is (x+4)^2 + (y-2)^2 = 5. We can rewrite this equation in standard form as follows:
(x+4)^2 + (y-2)^2 = 5 x^2 + 8x + 16 + y^2 - 4y + 4 = 5 x^2 + y^2 + 8x - 4y + 15 = 0
Therefore, the standard form of the given equation is x^2 + y^2 + 8x - 4y + 15 = 0.