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Write into standard form a with the given center and radius (X+4)^2+(y-2)^2=5

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Explanation:

The standard form of a circle with center (h,k) and radius r is given by the equation (x-h)^2 + (y-k)^2 = r^2 1.

In this case, the given equation is (x+4)^2 + (y-2)^2 = 5. We can rewrite this equation in standard form as follows:

(x+4)^2 + (y-2)^2 = 5 x^2 + 8x + 16 + y^2 - 4y + 4 = 5 x^2 + y^2 + 8x - 4y + 15 = 0

Therefore, the standard form of the given equation is x^2 + y^2 + 8x - 4y + 15 = 0.

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