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Find the nth term of the geometric sequence: 3, 5, 25/3, 125/9, ….

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Answer: 3 * (5/3)^(n-1)

Explanation:

The given sequence is a geometric sequence, which means that each term is obtained by multiplying the previous term by a fixed ratio. To find the nth term of a geometric sequence, we can use the formula:

a_n = a_1 * r^(n-1)

where a_n is the nth term, a_1 is the first term, r is the common ratio, and n is the term number.

In this case, the first term is 3, and the common ratio is 5/3. To see why, note that:

5/3 = 25/15 = (25/3) / (5) = (125/9) / (25/3)

So the nth term of the sequence is:

a_n = 3 * (5/3)^(n-1)

Therefore, the nth term of the given geometric sequence is 3 * (5/3)^(n-1)

User Thomas B Preusser
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