Question

Y = x² + 9x + 8
y = 7x + 8
(x1, y1), (x2, Y2) =

Answer 1

To find the points of intersection, we need to set the two equations equal to each other:

x^2 + 9x + 8 = 7x + 8

This simplifies to:

x^2 + 2x = 0

This equation factors to:

x(x + 2) = 0

Setting each factor equal to zero gives the solutions x1 = 0 and x2 = -2. Substituting these into the linear equation gives y1 = 8 and y2 = 6. So, the points of intersection are (0, 8) and (-2, 6).

Answer 2

(3, -1).

Explanation:

The solution to this system of linear equations 2x+3y=3 and 7x-3y=24 is (3, -1).