78.7k views
0 votes
A 400N copper object is placed on a steel surface.

a) What force of static friction will the object be subjected to if it is pushed with a force of 100N?

b) Which of the following is the smallest force that would cause the object to move?
1) 101N 2) 145N 3) 213N 4) 401N​

User KatariaA
by
6.7k points

1 Answer

5 votes

Step-by-step explanation:

To find the force of static friction, let's use the formula for static friction:

Force of static friction

Coefficient of static friction

×

Normal force

Force of static friction≤Coefficient of static friction×Normal force

However, if the applied force is less than the maximum static friction force, the static friction will be equal to the applied force.

Given:

Applied force (

applied

F

applied

): 100 N

Normal force (

normal

F

normal

): 400 N (assuming no other vertical forces are acting)

a) The object will experience static friction equal to the applied force because it's less than the maximum static friction. Therefore, the force of static friction will be

100

N

100N.

b) To determine the smallest force that would cause the object to move, it would be the force equal to the maximum static friction. The maximum static friction is

400

N

400N (the normal force), as this is the force needed to overcome static friction and initiate motion. Therefore, the smallest force that would cause the object to move is

equal to or greater than

400

N

equal to or greater than 400N. Among the options provided, the smallest force that would cause motion is 401N (Option 4).

User Starikcetin
by
7.4k points