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For the equation, y= (x-9)2 + 4 what is the axis of symmetry?

2 Answers

3 votes

Answer:

7/2

Explanation:

equation of the line is:

y = mx + b

given linear equation is:

y = (x - 9)2 + 4

= 2x - 18 + 4

y = 2x - 14

where, m = 2 and

b = -14

for a linear equation the axis of symmetry is:

x = -b / 2m

= -(-14) / 2(2)

= 14/4 = 7/2

thus, axis of symmetry, x = 7/2

User Kkyr
by
8.4k points
4 votes

Answer:

x = 9

Explanation:

The given equation is y = 2(x-9) + 4.

To find the axis of symmetry, we need to determine the x-value of the vertex. In this case, the equation is in the form y = mx + b, where m is the slope and b is the y-intercept.

The axis of symmetry is given by the equation x = -b/2a. In this case, a is the coefficient of x^2, which is 2.

So, plugging in the values from the equation y = 2(x-9) + 4, we have x = -(4)/2(2).

Simplifying, we get x = 9.

Therefore, the axis of symmetry for the equation y = 2(x-9) + 4 is x = 9.

User Aakash Anuj
by
8.6k points

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