To find the volume of the balloon when it is submerged in liquid nitrogen, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature.
First, we need to convert the temperatures to Kelvin. To convert from Celsius to Kelvin, we add
273.15. So, the room temperature of
25 oC is equivalent to 298.15 K, and the temperature of liquid nitrogen at
-196 oC is equivalent to 77 K.
Next, we can set up the equation using Charles's Law:
(Volume1 / Temperature1) =
(Volume2 / Temperature 2)
Where Volume1 is the initial volume of the balloon, Temperature is the initial temperature, Volume2 is the final volume of the balloon in liguid nitrogen, and Temperature is the temperature of the liquid nitrogen.
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Plugging in the given values:
(1.2 L / 298.15 K) = (Volume2 / 77 K)
Now, we can solve for Volume2 by cross-multiplying:
Volume2 = (1.2 L * 77 K) / 298.15 K
Simplifying the equation:
Volume2 = 0.310 L
Therefore, the volume of the balloon when it is in the liquid nitrogen is approximately 0.310 L.