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X^6 8=0 please helppp I’ll give u anything

User PALEN
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1 Answer

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To solve the equation X^6 + 8 = 0, we can follow these steps:

Step 1: Subtract 8 from both sides of the equation to isolate the term with the variable:

X^6 = -8

Step 2: Take the sixth root of both sides to solve for X. The sixth root of a number is the number that, when raised to the power of 6, gives the original number:

X = (-8)^(1/6)

Step 3: Simplify the expression on the right side of the equation. Since (-8)^(1/6) is a complex number, it can be expressed in multiple ways. One common way is to write it in polar form:

X = 2 * cos((π + 2kπ)/6) + i * sin((π + 2kπ)/6)

where k is an integer ranging from 0 to 5.

Step 4: Evaluate the expression for each value of k to obtain all possible solutions. Substituting k = 0, 1, 2, 3, 4, 5 into the equation will give us the different values of X.

For example, when k = 0:

X = 2 * cos(π/6) + i * sin(π/6)

X = 2 * (√3/2) + i * (1/2)

X = √3 + i/2

Similarly, when k = 1:

X = 2 * cos(π/3) + i * sin(π/3)

X = 2 * (1/2) + i * (√3/2)

X = 1 + √3i/2

And so on, for k = 2, 3, 4, and 5.

These are the different solutions for the equation X^6 + 8 = 0. Each value of X corresponds to a complex number on the complex plane.To solve the equation X^6 + 8 = 0, we can follow these steps:

Step 1: Subtract 8 from both sides of the equation to isolate the term with the variable:

X^6 = -8

Step 2: Take the sixth root of both sides to solve for X. The sixth root of a number is the number that, when raised to the power of 6, gives the original number:

X = (-8)^(1/6)

Step 3: Simplify the expression on the right side of the equation. Since (-8)^(1/6) is a complex number, it can be expressed in multiple ways. One common way is to write it in polar form:

X = 2 * cos((π + 2kπ)/6) + i * sin((π + 2kπ)/6)

where k is an integer ranging from 0 to 5.

Step 4: Evaluate the expression for each value of k to obtain all possible solutions. Substituting k = 0, 1, 2, 3, 4, 5 into the equation will give us the different values of X.

For example, when k = 0:

X = 2 * cos(π/6) + i * sin(π/6)

X = 2 * (√3/2) + i * (1/2)

X = √3 + i/2

Similarly, when k = 1:

X = 2 * cos(π/3) + i * sin(π/3)

X = 2 * (1/2) + i * (√3/2)

X = 1 + √3i/2

And so on, for k = 2, 3, 4, and 5.

These are the different solutions for the equation X^6 + 8 = 0. Each value of X corresponds to a complex number on the complex plane.

User Manoj Madanmohan
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8.8k points