Question

Students in an urban school were curious about how many children regularly eat breakfast. They conducted a survey, asking.

"Do you eat breakfast on a regular basis?" All 595 students in the school responded to the survey. The resulting data are shown in the two-way table. Suppose we select a student from the school at random. Define event F as getting a female student and vent B as getting a student who cats breakfast regularly.

Find P(BS).

A) 165/595 = 0.277

B) 295/595 = 0.496

C) 300/595 =0.504

D) 130/295 =0.441

E) 130/595 =0218

Answer 1

Suppose a student is selected from the school at random, the probability of getting a student who eats breakfast regularly (Event BS) is C) 300/595 =0.504.

How the probability is determined:

The number of students (female and male) who eat breakfast regularly = 300

The number of students (female and male) who do not eat breakfast regularly = 295

The total number of male students in the school = 320

The total number of female students in the school = 275

The total number of students surveyed = 595

Let the number of female students = Event F

Let the number of students who eat breakfast regularly = Event B

Let the probability of selecting a student who eats breakfast regularly = P(BS).

P(PBS) = 300/595 =0.504

Thus, the probability of getting a student who eats breakfast regularly (Event BS) is Option C.