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What values of b will cause 4x2 + bx + 25 = 0 to have one real solution?

User Hvollmeier
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1 Answer

2 votes

b = 20 and b = -20

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In order for the quadratic equation to have one real solution, the discriminant (b² - 4ac) must equal zero.

Using the values a = 4, b = b, and c = 25, we substitute them into the discriminant formula and set it equal to zero:

  • (b² - 4ac) = 0
  • b² - 4(4)(25) = 0
  • b² - 400 = 0
  • b² = 400
  • b = ± √400
  • b = ± 20

Therefore, the values of b that will cause the equation to have one real solution are b = 20 and b = -20.

User Lukegf
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