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What is the equation of he line that passes through (2, 3) and (-1, -12) in slope-intercept form

User CalebD
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1 Answer

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Answer: y = 5x - 7 or 5

Explanation:

To find the equation of a line that passes through two points, we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope of the line and b is the y-intercept.

The slope of the line passing through the points (2, 3) and (-1, -12) can be calculated as follows:

m = (y2 - y1) / (x2 - x1)

= (-12 - 3) / (-1 - 2)

= -15 / -3

= 5

Therefore, the slope of the line is 5.

To find the y-intercept, we can use one of the points and the slope of the line. Let’s use the point (2, 3):

Therefore, the slope of the line is 5.

To find the y-intercept, we can use one of the points and the slope of the line. Let’s use the point (2, 3):

y = mx + b

3 = 5(2) + b

3 = 10 + b

b = -7

Therefore, the y-intercept of the line is -7.

Thus, the equation of the line that passes through the points (2, 3) and (-1, -12) in slope-intercept form is:

y = 5x - 7

Therefore, the equation of the line in slope-intercept form is y = 5x - 7.

User Lmsasu
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