Question

the length of a rectangle is 20 cm longer than its width the area of the rectangle is 1000 cm^2 find the width and the length of the rectangle give your answer in surf form

Answer 1

.x= width

(x+20)= length

the area of ​​the rectangle is 1000 cm^2→x(x+20)=1000

x²+20x-1000=0

Δ = b²-4ac =20²-4(1*-1000)=4400

Δ is strictly positive, the equation x²+20x−1000=0 admits two solutions.

(-b-√Δ)/2a =(-20-20√11)/2=-10-10√11

(-b+√Δ)/2a =(-20+10√11)/2 = -10+10√11

a length is not negative, x =-10+10√11(cm)

width=-10+10√11(cm)

length=10+10√11(cm)

Area = (-10+10√11)(10+10√11)=-100-100V11+100V11+1100=1000cm²

Step by step explanation: