Question

Students in an urban school were curious about how many children regularly eat breakfast. They conducted a survey, asking.

"Do you eat breakfast on a regular basis?" All 595 students in the school responded to the survey. The resuking data are shown in the two-way table. Suppose we select a student from the school at random. Define event F as getting a female student and event B as getting a student who cats

Answer 1

The probability of not getting a student who eats breakfast regularly (
`P(B^C)` ) is 295/595 = 0.496. Option B

How to find the probability of the complement of event B

To find the probability of the complement of event B (
`P(B^C)` ), we need to find the probability of not getting a student who eats breakfast regularly.

Looking at the two-way table, the total number of students who do not eat breakfast regularly is given by the sum of the "No" responses in the "Eats breakfast regularly" column, which is 295.

The total number of students in the school is given as 595.

Therefore, the probability of not getting a student who eats breakfast regularly (
`P(B^C)` ) is 295/595.

Calculating this probability:

`P(B^C)` = 295/595 ≈ 0.495, which is approximately 0.496.

Therefore, the correct option is:

b. 295/595 = 0.496