Question

What is the vertex for of the equation

Y=-x2 + 12x-4

Answer 1

vertex = (6, 32 )

Explanation:

given a quadratic function in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

`x_(vertex)` = -
`(b)/(2a)`

y = - x² + 12x - 4 ← is in standard form

with a = - 1 and b = 12 , then

`x_(vertex)` = -
`(12)/(2(-1))` = -
`(12)/(-2)` = - (- 6) = 6

substitute x = 6 into the equation for corresponding y- coordinate

y = - 6² + 12(6) - 4 = - 36 + 72 - 4 = 36 - 4 = 32

vertex = (6, 32 )