Answer:13800 meters
Explanation: To find the distance covered by a car during a period of uniform acceleration, we can use the formula:
\[ distance = initial\ velocity \times time + \frac{1}{2} \times acceleration \times time^2 \]
Given:
- Initial velocity = 36 km/hr
- Acceleration = 10 m/s^2
- Time = 30 seconds
First, let's convert the initial velocity from km/hr to m/s:
1 km/hr = \(\frac{1000}{3600}\) m/s
Therefore, the initial velocity = \(\frac{36 \times 1000}{3600}\) m/s
Next, we can substitute the values into the formula:
\[ distance = \left(\frac{36 \times 1000}{3600}\right) \times 30 + \frac{1}{2} \times 10 \times 30^2 \]
Simplifying the equation:
\[ distance = \frac{36 \times 1000 \times 30}{3600} + 15 \times 900 \]
Now, calculate the distance:
\[ distance = 300 + 13500 \]
Finally, adding the values:
\[ distance = 13800 \]
Therefore, the car covers a distance of 13800 meters during the 30-second period of uniform acceleration.