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Whats the equation of the line that passes through (1,-3) and (4,6)

User Micky Loo
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1 Answer

4 votes

Answer:

y = 3x - 6

Explanation:

Given:

x₁ = 1

y₁ = -3

x₂ = 4

y₂ = 6


\boxed{(y-y_1)/(y_2-y_1)= (x-x_1)/(x_2-x_1) }


(y-(-3))/(6-(-3)) =(x-1)/(4-1)


(y+3)/(9) =(x-1)/(3)


(y+3)/(3) =x-1


y+3=3(x-1)


y=3x-6

User Samuel Eminet
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