Final answer:
Marty's distance d(t) from school is represented by the function d(t) = 5*t, with t being the time in hours since Marty left. The sequence of distances is 0, 5, 10, 15,... reflecting Marty's constant speed of 5 miles per hour. The graph of this function is a line through the origin with a slope of 5.
Step-by-step explanation:
Marty's distance from school can be represented as a sequence and an equation in function notation. We first set 't' as time in hours since Marty left school. Given Marty runs at a constant speed of 5 miles per hour, this relationship is linear and is simply described by the function d(t) = 5*t, where d is the distance from school in miles.
The sequence would look like this: At t = 0 (when Marty just left school), his distance d(0) is 0 miles, at t = 1 (1 hour after he left), his distance d(1) is 5 miles, at t = 2, d(2) is 10 miles, and so forth. So the sequence would be 0, 5, 10, 15, etc.
The graph of the sequence will be a straight line going through the origin (0,0) and slanting upwards. The slope of the line equals the constant speed, which in this case is 5 miles per hour. This reflects that every hour, Marty moves 5 miles further from the school. The positioning and slope of the line graphically demonstrate the relationship derived in the function d(t) = 5*t.
Learn more about Distance-Time Relationship