The probability of selecting a student with a partime job without a car is 0.2 and the probability of p(no car | does not have a part time job) is 0.571
Using the parameters given for our Calculation;
- N(students with part time jobs without a car) = 30
- N(Total number surveyed) = 108 + 42 = 150
Probability = Number of favorable outcomes/ Total possible outcomes
1.)
P(Students with part time job without a car) = 30/150 = 0.2
2.)
p(no car | does not have a part time job)
Using the concept;
P(A|B) = P(AnB) / P(B)
p(no car | does not have a part time job) = 24/(18+24)
= 24/42
= 0.571
Complete Question:
The table below shows the number of students that do or do not have their own car and whether they have part time jobs.
1. p(a student with a part time job without a car)
2. p(no car | does not have a part time job)