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A ball is thrown vertically upward from ground level at a rate of 119 feet per second. Use the projectile formula

h
=

16
t
2
+
v
0
t
+
h
0
to find how long it will take the ball to reach its maximum height, and then find the maximum height the ball reaches. [Recall that
v
0
is the initial velocity of the object and
h
0
is the inital height of the object.]

Answer: The stone reaches its maximum height after after

Select an answer
. The maximum height the stone reaches is

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Note: Round any numerical responses to two decimal places. If there are multiple answers, separate them with commas.

A ball is thrown vertically upward from ground level at a rate of 119 feet per second-example-1

1 Answer

3 votes

Answer:

h(t) = -16t² + 119t

h'(t) = -32t + 119 = 0

32t = 119

t = 3.72 seconds

The stone reaches its maximum height after 3.72 seconds.

h(119/32) = -16(119/32)² + 119(119/32)

= 221.27 feet

The maximum height the stone reaches is 221.27 feet.

User Mikeymo
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