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Factoring special products. factor and solve: 16y^2-81z^2

User Jschreiner
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1 Answer

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Answer: The solutions for the factored expression are:

y = -9z/4 and y = 9z/4.

Explanation:

To factor and solve the expression 16y^2 - 81z^2, we can recognize that it is a difference of squares. The formula for factoring a difference of squares is (a^2 - b^2) = (a + b)(a - b).

In this case, we have 16y^2 - 81z^2, which can be expressed as (4y)^2 - (9z)^2. Now, we can see that a = 4y and b = 9z.

Using the formula for factoring a difference of squares, we can factor the expression as follows:

16y^2 - 81z^2 = (4y + 9z)(4y - 9z)

Now we have factored the expression into two binomial terms: (4y + 9z) and (4y - 9z).

To solve the factored expression, we can set each binomial term equal to zero and solve for the variables:

Setting 4y + 9z = 0, we can solve for y:

4y = -9z

y = -9z/4

Setting 4y - 9z = 0, we can solve for y:

4y = 9z

y = 9z/4 Therefore, the solutions for the factored expression are:

y = -9z/4 and y = 9z/4.

User Ferdinand Neman
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