To 2x^2 - 4x - 6 = 0
Use -> x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 2, b = -4, and c = -6. Plugging in these values, we get:
x = (-(-4) ± √((-4)^2 - 4(2)(-6))) / (2(2))
Simplifying further, we have:
x = (4 ± √(16 + 48)) / 4
x = (4 ± √64) / 4
x = (4 ± 8) / 4
This gives us two solutions:
x1 = (4 + 8) / 4 = 3
x2 = (4 - 8) / 4 = -1/2
So the solutions to the equation 2x^2 - 4x - 6 = 0 are x = 3 and x = -1/2.