Question

A student dropped a 0.2 kg cell phone from the edge of a 1.2 m table in physics class. Assume air resistance is negligible

Answer 1

Using the equation h = 1/2gt^2, where h is the height of the table (1.2 m), and g is the acceleration due to gravity (9.8 m/s^2), we can solve for t, which represents the time.

By rearranging the equation, we have t = √(2h/g).

Plugging in the values, we get:
t = √(2 * 1.2 / 9.8)

Simplifying further:
t = √(0.2449)

So the time it takes for the cell phone to fall is approximately 0.495 seconds.