Final answer:
The standard error for the difference between two sample proportions with p1 = p2 = 0.06 and sample sizes of 920 and 1100 is approximately 0.0106.
Step-by-step explanation:
To calculate the standard error for the difference between two sample proportions when the population proportions are assumed to be equal (p1 = p2 = 0.06), the formula is:
SE = √[(p(1-p)) (1/n1 + 1/n2)],
where p is the common population proportion, n1 and n2 are the sample sizes. In this case, using p = 0.06, n1 = 920, and n2 = 1100:
SE = √[(0.06 * (1 - 0.06)) (1/920 + 1/1100)] = sqrt[(0.06 * 0.94) (0.00108696 + 0.00090909)] = sqrt[(0.0564) (0.00199605)] = sqrt[0.0001126026] ≈ 0.0106.
Therefore, the standard error for the difference between the sample proportions is approximately 0.0106.