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A table lamp emits light in the shape of a hyperbola. If the hyperbola is modeled by the equation 25x^2 – 144y^2 + 3,600 = 0, which of the following equations represents the boundaries of the light?

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The appropriate expression is y equals five twelfths x and y equals negative five twelfths x. Option A

How do we solve for the appropriate expression?

To find the expression, we first need to rewrite the given equation of the hyperbola in terms of y:

25x² - 144y² + 3,600 = 0

25x² - 144y² = - 3,600

(25x²/- 3,600) - ( 144y²/- 3,600) = 1

x²/25 - y²/144 = 1

x²/-25 - y²/-144 = 1

y = ±(b/a)x

In this case, a² =144 and b² =25, thus a=12 and b=5. The slopes of the asymptotes are ± 5/12

y = (5/12)x

y = (5/12)x

Full question

A table lamp emits light in the shape of a hyperbola. If the hyperbola is modeled by the equation 25x2 – 144y2 + 3,600 = 0, which of the following equations represents the boundaries of the light?

  • y equals five twelfths x and y equals negative five twelfths x
  • y equals twelve fifths x and y equals negative twelve fifths x
  • y equals five thirteenths x and y equals negative five thirteenths x
  • y equals thirteen fifths times x and y equals negative thirteen fifths times x
User Nick Russo
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