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Help this is due at 11 (ACTUALLY THIS IS REAL)

Help this is due at 11 (ACTUALLY THIS IS REAL)-example-1
Help this is due at 11 (ACTUALLY THIS IS REAL)-example-1
Help this is due at 11 (ACTUALLY THIS IS REAL)-example-2

2 Answers

4 votes

Answer:
a^5

Explanation:


\sqrt[3]{a^15} is basically another way of writing
a^15 / a^3 which is just 15/3 to give you 5

User BearsEars
by
7.7k points
5 votes

Answer:

1st one:
1.804 * 10^7

2nd one:
\sf a^5

Explanation:

1st part:

Product in Scientific Notation:

To find the product of 41 and
\sf 4.4 * 10^5 in scientific notation, follow these steps:


\sf 41 * (4.4 * 10^5) = (41 * 4.4) * 10^5

Calculate the numerical part:


\sf 41 * 4.4 = 180.4

So, the product in scientific notation is:


\begin{aligned} 1.804 * 10^2 * 10^5 & = 1.804 * 10^(2+5) \\\\ & = \boxed{1.804 } * 10^{\boxed{\sf 7 }} \end{aligned}

2nd Part:

Simplifying
\sf \sqrt[3]{a^(15)}:

The property used here is the rule for exponentiation when we have a power raised to another power. The rule is:


\sf (a^m)^n = a^(mn)

In wer case,
\sf \sqrt[3]{a^(15)} means raising
\sf a^(15) to the power of
\sf (1)/(3) because the cube root is the same as raising to the power of
\sf (1)/(3). So, applying the exponent rule:


\sf (a^(15))^{(1)/(3)} = a^{15 * (1)/(3)} \\\\ = a^5

Therefore,
\sf \sqrt[3]{a^(15)} simplifies to
\sf a^5. This is based on the property that when we take the cube root of a number raised to a power, we divide the exponent by the root.

User Jordan Reiter
by
7.4k points