Question

A plumber and his assistant work together to replace the pipes in an old house. The plumber charges $50 an hour for his own labor and $25 an hour for his assistant's labor. The plumber works twice as long as his assistant on this job, and the labor charge on the final bill is $4375. How long did the plumber and his assistant work on this job?

Answer 1

70 hours is how long the plumber and his assistant worked

Answer 2

x in hours

x= the working time of the assistant

2x = the plumber's working time

25x+2(50x)=4375

25x+100x=4375

125x=4375

x=35

the assistant worked 35 hours

the plumber worked 70 hours

Explanation: