Question

What’s the answer after being simplified

Answer 1

`\text{Here we use the pythagorean theorem in }\triangle s\ \text{BCD and ACD.}\\\text{In }\triangle \text{ACD},\\\text{CD}^2=\text{AC}^2-\text{AD}^2=9^2-2^2\\\text{or, CD}^2=77`

`\text{In }\triangle \text{BCD},\\\text{BC}^2=\text{CD}^2+\text{BD}^2=77+4=81\\\text{or, }\text{BC}=9`

`\text{So, Perimeter of }\triangle \text{ABC}=\text{AB+BC+AC = (AD+BD)+9+9}=\text{2+2+18 = 22}`