Question

Question 5 If h(t)=16t−4 and g(t)=3−2t , what is the value of g(−1)−h(1)? Multiple choice question. cross out A) −21 cross out B) −16 cross out C) −11 cross out D) −7

Answer 1

D) -7

Explanation:

To solve this question, we need to substitute the value of t into the functions g(t) and h(t) and then subtract the two results.

First, let's calculate g(-1):

g(-1) = 3 - 2(-1)

g(-1) = 5

Next, let's calculate h(1):

h(1) = 16(1) - 4

h(1) = 12

Finally, let's subtract h(1) from g(-1):

g(-1) - h(1) = 5 - 12

g(-1) - h(1) = -7

Therefore, the value of g(-1) - h(1) is -7.

So, the answer is D) -7