Question

What is the solution of the system of equations? *Hint - multiply each term in one of the equations by a common factor to create opposites that cancel out. 13x - 6y = 2 -9x + 12y = 30 Enter your answer in the boxes.

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GUYS PLEASE HELP ME

Answer 1

x = 2 , y = 4

Explanation:

given the system of equations

13x - 6y = 2 → (1)

- 9x + 12y = 30 → (2)

multiplying (1) by 2 and adding the result to (2) will eliminate y

26x - 12y = 4 → (3)

add (2) and (3) term by term to eliminate y

(- 9x + 26x) + (12y - 12y) = 30 + 4

17x + 0 = 34

17x = 34 ( divide both sides by 17 )

x = 2

substitute x = 2 into either of the 2 original equations and solve for y

substituting into (1)

13(2) - 6y = 2

26 - 6y = 2 ( subtract 26 from both sides )

- 6y = - 24 ( divide both sides by - 6 )

y = 4

The solution is x = 2, y = 4