To find the values of x, set the lengths of the corresponding sides of the two triangles equal to each other and solve for x =4.
We are given two triangles, ABC and DBC, with a common base BC. In triangle ABC, side AC is represented by 4x-7 and side AB is represented by 2x+3. In triangle DBC, side DB is represented by 2x+1 and side DC is represented by 3x-1.
To find the values of x, we can set the lengths of the corresponding sides equal to each other and solve for x. So, we have:
4x-7 = 2x+1 (lengths of AC and DB)
2x+3 = 3x-1 (lengths of AB and DC)
Solving these equations, we find x = 4 and x = 4, respectively. Therefore, the value of x is 4.
The complete question is- Consider two triangles, ABC and DBC, sharing a common base BC. In triangle ABC, the length of side AC is represented by 4x−7, and the length of side AB is represented by 2x+3. In triangle DBC, the length of side DB is represented by 2x+1, and the length of side DC is represented by 3x−1.
Determine all values of x for which the two triangles, ABC and DBC, are congruent.