Question

A pebble is stuck in a tire with a radius of 0.6 m. The stone is experiencing a centripetal acceleration of 48 m/s?. What is its velocity?

Answer 1

• 5.36 m/s

Step-by-step explanation:

To find :-

• Velocity of the stone.

Answer :-

We are here given that the radius of the circular path is 0.6m and it's experiencing a centripetal acceleration of 48m/s².

As we know that,

• Centripetal acclⁿ = v²/r .

On substituting the respective values, we have;

→ v²/0.6m = 48m/s²

→ v² = 48 * 0.6 m²/s²

→ v = √{28.8 m²/s²}

→ v = 5.36m/s

Henceforth the velocity of the stone is 5.36m/s.