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Solve the system of equations by elimination.


x–2y–z=

3

2x–3y–z=

2
x–y+3z=

9
,
,

User Jonchang
by
7.3k points

1 Answer

4 votes

The values of x,y and z in the equations are -5, 4 and 0 respectively.

How to solve simultaneous equations using elimination method.

Let's solve the system of equations by elimination.

Given

-x - 2y - z = -3 ------------------1

-2x - 3y - z = -2-----------------2

x - y + 3z = -9 ------------------3

Multiply the first equation by 2

-2x - 4y - 2z = -6

-2x - 3y - z = -2

Subtract equations 2 from the product

-y - z = -4 ---------------4

Add equations 1 &3 to eliminate x:

-x - 2y - z = -3

x - y + 3z = -9

-3y + 2z = -12 -----------------5

Let's solve equations 4 and 5 simultaneously

Multiple equation 4 by 3 and subtract the result from equation 5.

-3y -3z = -12

-3y + 2z = -12

5z = 0

z = 0

Substitute into equation 4 to find y

-y - z = -4

-y -0 = -4

-y = -4

y = 4

Substitute z = 0 and y = 4 into equation 1 to find x

-x - 2y - z = -3

-x -2(4) -0 = -3

-x - 8 = -3

-x = -3+8

= 5

x = -5

The values of x,y and z in the equations are -5, 4 and 0 respectively.

User Rajendran T
by
7.9k points