79.1k views
1 vote
Can anyone help me with this?
lesson, solving right triangles

Can anyone help me with this? lesson, solving right triangles-example-1

1 Answer

3 votes

Answer:

θ ≈ 25°

Explanation:

using the sine ratio in the right triangle

sinθ =
(opposite)/(hypotenuse) =
(3)/(7) , then

θ =
sin^(-1) (
(3)/(7) ) ≈ 25° ( to the nearest whole degree )

User Don Subert
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories