Question

I have a calculus one question about derivatives as rates of change when it comes to population picture included

Answer 1

Okay, here we have this:

Considering the provided information, we are going to calculate the requested population, so we obtain the following:

Let us remember that we are talking about linear growth, therefore we will solve for the following formula:

`\begin{gathered} f(x)=b+mx \\ 68000=17000+m(2) \\ 51000=2m \\ m=(51000)/(2) \\ m=25500 \end{gathered}`

Now, let's calculate the population after one year:

`\begin{gathered} f(x)=17000+25500x \\ f(1)=17000+25500(1) \\ f(1)=17000+25500 \\ f(1)=42500 \end{gathered}`

Finally we obtain that after one year the population will be 42500.