Answer:
Step-by-step explanation:
The ball is thrown initially in horizontal direction, so it's vertical velocity would be 0 .
According to the question it should have 38.5m/s velocity in vertically direction, that is final velocity of the baseball.
Taking downward direction positive, we can apply equation of motion in vertical direction as ,
→ 2as = v² - u²
→ 2* g(i.e. ≈ 9.8 m/s²) s = (38.5 m/s)² - 0²
→ 2 * 9.8 * s = 38.5²
→ s = 38.5²/19.6 m
→ s = 75.62m
Henceforth the required height is 75.25m.