Question

Assuming the validity of Raoults law do the following calculations for benzene(1)

toluene (2) system.


a)Given x1, = 0.33 and T= 100°C, find y1, and P
b)Given y1, = 0.33 and T= 100°C, find x1; and P
c) Given x1, = 0.33 and P= 120 KPa, find y1, and T.

The Antoine equation and parameters are given below:

In P(sat)/KPa=A-(B/T+C) (T inºC)



Compounds

Benzene
A=13.8594
B=2773.78
C=220.07

Toluene
A=14.0098
B=3103.01
C=219.79

Answer 1

To solve these equations using the Antoine equation, we can rearrange it to find the missing variable.

a) Given x1 = 0.33 and T = 100°C, we need to find y1 and P.

For Benzene:

A = 13.8594

B = 2773.78

C = 220.07

Using the Antoine equation for Benzene:

P(sat)/KPa = A - (B / (T + C))

Plugging in the values:

P(sat) / KPa = 13.8594 - (2773.78 / (100 + 220.07))

Now, we can solve for P(sat).

P(sat) = (13.8594 - (2773.78 / 320.07)) * 120 (since P is given as 120 KPa)

Next, we can calculate y1 using the equation:

y1 = x1 * P(sat)

Plugging in the values:

y1 = 0.33 * P(sat)

b) Given y1 = 0.33 and T = 100°C, we need to find x1 and P.

The process is similar to part a, but we rearrange the equation to find x1:

x1 = y1 / P(sat)

c) Given x1 = 0.33 and P = 120 KPa, we need to find y1 and T.

Again, we rearrange the equation to solve for the missing variable:

P(sat) = A - (B / (T + C))

Then we can use the following equation to find y1:

y1 = x1 * P(sat)

These equations can be used to solve for the missing variables by substituting the given values and calculating accordingly.

Step-by-step explanation: