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which of the following equations defines a line that is parallel to the line y=-3/4x-4 and passes through the point (3,-1)

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Answer:

Explanation:

The slope of the parallel line is -3/4.

Using the point-slope form:-

y - y1 = m(x - x1) where m=slope and (x1, y1) is a point on the line.

Here m = -3/4, x1 = 3 and y1 = -1, so we have:

y - (-1) = -3/4(x - 3)

y + 1 = -3/4x + 9/4

y = -3/4x + 9/4 - 1

y = -3/4x + 5/4 is the answer.

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