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9x^2-36x-4y^2-8y-4=0
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9x^2-36x-4y^2-8y-4=0

User Pepacz
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Answer:

Explanation:


9x^2-36x-4y^2-8y-4=0\\(3x-6)^2-36-(2y+2)^2+4-4=0\\(3x-6)^2-(2y+2)^2=36\\((3x-6)/(6))^2-((2y+2)/(6))^2=1\\((x-2)/(2))^2-((y+1)/(3))^2=1

User Hsan
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