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if a snowball melts so that its surface area decreases at a rate of 3 cm2/min, find the rate (in cm/min) at which the diameter decreases when the diameter is 10 cm. (round your answer to three decimal places.) cm/min

User Snowbldr
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Final answer:

The rate at which the diameter decreases when the diameter is 10 cm is -0.119 cm/min.

Step-by-step explanation:

We can use the formula for the surface area of a sphere, which is A=4πr², where A is the surface area and r is the radius (or half the diameter) of the sphere.

Given that the surface area is decreasing at a rate of 3 cm²/min, we can find the rate at which the radius is decreasing.

Using the chain rule, we can relate the rates of change of the surface area and the radius as follows:

  • dA/dt = (dA/dr)(dr/dt)
  • -3 = (8πr)(dr/dt)
  • (dr/dt) = -3/(8πr)

Substituting the given diameter of 10 cm, we can find the rate at which the diameter is decreasing:

  • (dr/dt) = -3/(8π(10/2))
  • (dr/dt) = -0.119 cm/min (rounded to three decimal places)
User JoeCo
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