The calculated boundaries of the distribution is 92.98 to 114.92
How to calculate the missing and indicated values
From the question, we have the following parameters that can be used in our computation:
The mean of the normal distribution = 103.9 ft
The standard deviation = 73.9 ft
The random sample n is given as n = 180 trees.
So, we have
Standard Error, E = SD/√n
This gives
E = 73.9/√180
Evaluate
E = 5.51
Using the above as a guide, we have the following:
Upper bound = 103.9 + 2 * 5.51 = 114.92
Lower bound = 103.9 - 2 * 5.51 = 92.98
Hence, the boundaries is 92.98 to 114.92