Question

I need some help please out

Answer 1

Question:

Solution:

Let the following equation:

`\sqrt[]{12-x}=\text{ x}`

this is equivalent to:

`(\sqrt[]{12-x})^2=x^2`

this is equivalent to:

`12-x=x^2`

this is equivalent to:

`x^2+x-12=\text{ 0}`

thus, we can conclude that

x= 3.