50.6k views
1 vote
How many moles are present in 3.5×10²⁴ particles of K2SO4

User Gilsha
by
7.4k points

1 Answer

3 votes
Since one molecule of K2SO4 contains 7 atoms {Two Potassium(K), One Sulphur (S) and Four Oxygen (O)}.
Thus in 5 moles there will be,

6.022 × 10²³ × 7 × 5 =

210.77 × 10²³ or 2.1077 × 10²⁵ or 21077 × 10²¹ atoms.

Here, 6.022 × 10²³ is the Avogadro number
User Jacob Rastad
by
7.5k points