Final answer:
The maximum tolerable pressure difference between the external and inner ear is 500,000 Pa. A person can dive to a maximum depth of approximately 51.02 meters in fresh water before rupturing an eardrum.
Step-by-step explanation:
The maximum tolerable pressure difference between the external and inner ear can be calculated using the formula:
Pressure difference = Force / Area
Given that the force required to rupture the eardrum is 5.0 N and the cross-sectional area of the membrane is 1.0 cm2, we can substitute these values into the formula:
Pressure difference = 5.0 N / 1.0 cm2
Converting the area to m2, we get:
Pressure difference = 5.0 N / (1.0 cm2 / 10,000)
Simplifying, we find that the maximum tolerable pressure difference is 500,000 Pa.
To calculate the maximum depth a person can dive before rupturing an eardrum, we can use the concept of pressure and depth in a fluid:
Pressure = ρgh
Where ρ is the density of the fluid (fresh water), g is the acceleration due to gravity, and h is the depth. Rearranging the formula, we get:
h = Pressure / (ρg)
Plugging in the maximum tolerable pressure difference (500,000 Pa) and the density of fresh water (1000 kg/m3), we can calculate the maximum depth:
h = 500,000 Pa / (1000 kg/m3 * 9.8 m/s2)
Simplifying, we find that a person can dive to a maximum depth of approximately 51.02 meters in fresh water before rupturing an eardrum.