For every real number
less than or equal to
, the polynomial will have one real root (which is
) and two non-real roots that are complex conjugates of each other, and these roots will be in arithmetic progression.
To find the real numbers
such that the roots of the polynomial
form an arithmetic progression and are not all real, we'll need to determine the conditions that these roots must satisfy.
Let's say the three roots are
, and
, where
is the middle root of the arithmetic progression and
is the common difference. Since not all roots are real, one root must be real (the middle root
and the other two must be complex conjugates.
The sum of the roots, given by Vieta's formulas, is equal to the coefficient of
with the opposite sign. For this polynomial, the sum of the roots is . So we have:
![\[ r + (r+d) + (r-d) = 3 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/owbn8mecyhxywvi36tlhc2er5s7f4rk158.png)
![\[ 3r = 3 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/hkbaz3ttv5racz33o7ygntkdghr06t7u27.png)
![\[ r = 1 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/1xen9pcoy6z2ia7gaa9r4dl6b8di5h0dpd.png)
The middle root
is 1. So the roots are
,
, and
. Because two of the roots are complex conjugates,
must be imaginary. Let
, where
is a real number and
is the imaginary unit.
Now we consider the product of the roots. For complex conjugates,
, because
. The product of the roots is given by the constant term
of the polynomial with the opposite sign:
![\[ (1)(1+bi)(1-bi) = -a \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/v0fhw8v1z2g0698do533bmcntg11b6s9p7.png)
![\[ 1+b^2 = -a \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/5a1n6a719s4l8fjlx3isgp7236x2qe5geq.png)
![\[ a = -1 - b^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/r4abeegv9e7h1qxj63yp585cgzmdi0z5qp.png)
The polynomial is
, and we want to ensure that when
, the polynomial has one real root and two complex conjugate roots. However, since we already established that the roots are in arithmetic progression with a common difference of \( bi \), we have effectively ensured that the non-real roots are complex conjugates by construction.
So the possible values for
are those for which
is a real number. That is,
can take any value of the form
where
is a real number. This gives us a range of values for
, since
is always non-negative:
![\[ a \leq -1 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/3diuoo7s1bctyjfjfj1xvcgl7hzygagqyy.png)
For every real number
less than or equal to
, the polynomial will have one real root (which is
) and two non-real roots that are complex conjugates of each other, and these roots will be in arithmetic progression.