Question

A 0.15kg baseball is moving at 26 m/s is slowed to a stop by a who exerts a constant force of -390N how long does it take for the ball to stop

Answer 1

0.01 s

Step-by-step explanation:

Use Newton's second law to find the acceleration.

F = ma

-390 N = (0.15 kg) a

a = -2600 m/s²

Given:

u = 26 m/s

v = 0 m/s

a = -2600 m/s²

Find: t

v = u + at

0 m/s = 26 m/s + (-2600 m/s²) t

t = 0.01 s

It takes 0.01 s.