442,762 views
30 votes
30 votes
Solve the equation 42+7c - 5 = 0 using the quadratic formula

Solve the equation 42+7c - 5 = 0 using the quadratic formula-example-1
User John Alexander Betts
by
2.7k points

1 Answer

17 votes
17 votes

The equation is:


4c^2+7c-5=0

so we can use the cuadratic equation so:


\begin{gathered} c=\frac{-b\pm\sqrt[]{b^2-4(a)(c^(\prime))}}{2(a)} \\ \text{where} \\ a=4 \\ b=7 \\ c^(\prime)=-5 \end{gathered}

So if we replace in the equation we will have:


c=\frac{-7\pm\sqrt[]{7^2-4(4)(-5)}}{2(4)}

So we simplify to solve the problem so:


c=\frac{-7\pm\sqrt[]{129}}{8}

User Dlf
by
2.6k points