Question

X^2-32x+c complete the square

Answer 1

To finish the square for \(x^2 - 32x + c\), we'll zero in on the \(x\) terms. The \(c\) term recommends that we're working with a quadratic condition, yet we'll require a smidgen more data to completely settle for \(c\) and complete the square.

Explanation:

Without a doubt, to finish the square for \(x^2 - 32x + c\), we really want to take the coefficient of \(x\), which is \(- 32\), partition it by 2, square the outcome, and add that to the two sides of the situation.

The coefficient of \(x\) is \(- 32\), a big part of that is \(- 16\), and when squared, it's \(256\). In this way, to finish the square, we add \(256\) to the two sides:

\(x^2 - 32x + 256 = c + 256\)

This makes an ideal square three fold on the left side: \((x - 16)^2 = c + 256\)

Answer 2

We divide the -32 by 2 and square the result
So we have
X^2 - 33c + (-16)^2
+ x^2 -32c + 256