Question

In the diagram below, quadrilateral ABCD has vertices A(-5,1), B(6,-1),C(3,5), and D(-2,7). What are the coordinates of the midpoint of the diagonal AC? a. (-1, 3) b. (1, 3) c. (1, 4) d. (2, 3)

Answer 1

The coordinates of the midpoint of the diagonal AC is (-1, 3) (Option A)

How to calculate the coordinate of the midpoint?

The coordinates of the midpoint of the diagonal AC is calculated by applying the following formula as shown below;

The midpoint formula is given as;

`(x, y) = \left [(x_1 \ + \ x_2)/(2) , (y_1 \ + \ y_2)/(2)\right]`

where;

• x₁ and x₂ are the coordinates in x - direction
• y₁ and y₂ are the coordinates in y - direction

The coordinates of the midpoint of the diagonal AC is calculated as;

A ⇒ (x₁, y₁) = (-5, 1)

C ⇒ (x₂, y₂) = (3, 5)

`(x, y) = \left [(-5 + 3)/(2) , (1 + 5)/(2)\right]\\\\(x,y) = \left [(-2)/(2) , (6)/(2)\right]\\\\(x, y) = (-1, 3)`